Custom Query (1030 matches)

As the subject says, (abs #c(1d300 1d300)) signals an overflow. But in fact, the answer is approximately 1.414d300, which still fits in a double-float.

The implementation is probably just doing sqrt(x^2+y^2). A better answer can be achieved using |x|*sqrt(1+(y/x)^2) if |x| >= |y|, with obvious modifications for |x| <= |y|.

(log #c(1d300 1d300)) signals overflow, but it shouldn't since the absolute value of #c(1d300 1d300) fits in a double-float.

This could be related to ticket:830.

(sqrt #c(1d300 1d300)) signals an overflow, but the square root is approximately #c(1.10d150 4.55d149).

Could be related to ticket:830 and ticket:831.